648. Replace Words
Tags: ‘Hash Table’, ‘Trie’
In English, we have a concept called root
, which can be followed by some other words to form another longer word - let's call this word successor
. For example, the root an
, followed by other
, which can form another word another
.
Now, given a dictionary consisting of many roots and a sentence. You need to replace all the successor
in the sentence with the root
forming it. If a successor
has many roots
can form it, replace it with the root with the shortest length.
You need to output the sentence after the replacement.
Example 1:
Input: dict = ["cat", "bat", "rat"] sentence = "the cattle was rattled by the battery" Output: "the cat was rat by the bat"
Note:
- The input will only have lower-case letters.
- 1 <= dict words number <= 1000
- 1 <= sentence words number <= 1000
- 1 <= root length <= 100
- 1 <= sentence words length <= 1000
Solution
方法1:trie标准用法 49% 75%
class Solution {
public String replaceWords(List<String> dict, String sentence) {
Trie trie = new Trie();
for (String word: dict) {
trie.insert(word);
}
StringBuilder sb = new StringBuilder();
String[] words = sentence.split("\\s+");
for (String word: words) {
sb.append(trie.findShortestPrefixWord(word) + " ");
}
return sb.toString().trim();
}
private class Node {
private Node[] children;
private boolean isWord;
private String word;
private Node() {
children = new Node[26];
}
}
private class Trie {
private Node root;
private Trie() {
root = new Node();
}
private void insert(String word) {
Node p = root;
for (int i = 0; i < word.length(); i++) {
int index = (int)(word.charAt(i) - 'a');
if (p.children[index] == null) {
p.children[index] = new Node();
}
p = p.children[index];
}
p.isWord = true;
p.word = word;
}
private String findShortestPrefixWord(String word) {
Node p = root;
for (int i = 0; i < word.length(); i++) {
int index = (int)(word.charAt(i) - 'a');
if (p.children[index] == null) {
break;
}
if (p.children[index].isWord) {
return p.children[index].word;
}
p = p.children[index];
}
return word;
}
}
}