297. Serialize and Deserialize Binary Tree
Tags: ‘Tree’, ‘Design’
Serialization is the process of converting a data structure or object into a sequence of bits so that it can be stored in a file or memory buffer, or transmitted across a network connection link to be reconstructed later in the same or another computer environment.
Design an algorithm to serialize and deserialize a binary tree. There is no restriction on how your serialization/deserialization algorithm should work. You just need to ensure that a binary tree can be serialized to a string and this string can be deserialized to the original tree structure.
Example:
You may serialize the following tree:
1
/ \
2 3
/ \
4 5
as "[1,2,3,null,null,4,5]"
Clarification: The above format is the same as how LeetCode serializes a binary tree. You do not necessarily need to follow this format, so please be creative and come up with different approaches yourself.
Note: Do not use class member/global/static variables to store states. Your serialize and deserialize algorithms should be stateless.
Solution
方法1: 来自九章,BFS Iterative + Queue序列化和反序列化
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class Codec {
// Encodes a tree to a single string.
public String serialize(TreeNode root) {
// BFS using queue
if (root == null) {
return "{}";
}
List<TreeNode> queue = new ArrayList<>();
queue.add(root);
// iterate using index while adding elements
for (int i = 0; i < queue.size(); i++) {
TreeNode node = queue.get(i);
if (node == null) {
continue;
}
queue.add(node.left);
queue.add(node.right);
}
// remove trailing nulls
while(queue.get(queue.size() - 1) == null) {
queue.remove(queue.size() - 1);
}
StringBuilder sb = new StringBuilder();
sb.append("{");
sb.append(queue.get(0).val); // must have first 1
for (int i = 1; i < queue.size(); i++) {
if (queue.get(i) == null) {
sb.append(",#");
} else {
sb.append(",");
sb.append(queue.get(i).val);
}
}
sb.append("}");
return sb.toString();
}
// Decodes your encoded data to tree.
public TreeNode deserialize(String data) {
if (data == null || data.equals("{}")) {
return null;
}
String[] vals = data.substring(1, data.length() - 1).split(",");
List<TreeNode> queue = new ArrayList<>();
TreeNode root = new TreeNode(Integer.parseInt(vals[0]));
queue.add(root);
int index = 0; // current parent to append
boolean isLeft = true;
for (int i = 1; i < vals.length; i++) {
if (!vals[i].equals("#")) {
TreeNode node = new TreeNode(Integer.parseInt(vals[i]));
if (isLeft) {
queue.get(index).left = node;
} else {
queue.get(index).right = node;
}
queue.add(node);
}
if (!isLeft) {
index++; // increment index when two times
}
isLeft = !isLeft; // flip every time
}
return root;
}
}
// Your Codec object will be instantiated and called as such:
// Codec codec = new Codec();
// codec.deserialize(codec.serialize(root));
方法2:leetcode DFS + Recursive
public class Codec {
// Encodes a tree to a single string.
public String serialize(TreeNode root) {
StringBuilder sb = new StringBuilder();
return serialize(root, sb).toString();
}
private StringBuilder serialize(TreeNode root, StringBuilder sb) {
if (root == null) { // end case
sb.append("#");
return sb;
}
sb.append(root.val).append(",");
serialize(root.left, sb).append(",");
serialize(root.right, sb);
return sb;
}
// Decodes your encoded data to tree.
public TreeNode deserialize(String data) {
Queue<String> queue = new LinkedList<>();
queue.addAll(Arrays.asList(data.split(",")));
return deserialize(queue);
}
private TreeNode deserialize(Queue<String> queue) {
String val = queue.poll();
if ("#".equals(val)) {
return null;
}
TreeNode root = new TreeNode(Integer.valueOf(val));
root.left = deserialize(queue);
root.right = deserialize(queue);
return root;
}
}