589. N-ary Tree Preorder Traversal
Tags: ‘Tree’
Given an n-ary tree, return the preorder traversal of its nodes' values.
For example, given a 3-ary
tree:
Return its preorder traversal as: [1,3,5,6,2,4]
.
Note:
Recursive solution is trivial, could you do it iteratively?
Solution
/*
// Definition for a Node.
class Node {
public int val;
public List<Node> children;
public Node() {}
public Node(int _val,List<Node> _children) {
val = _val;
children = _children;
}
};
*/
class Solution {
public List<Integer> preorder(Node root) {
List<Integer> result = new ArrayList<>();
traversal(root, result);
return result;
}
private void traversal(Node node, List<Integer> result) {
if (node == null) return;
result.add(node.val);
if (node.children != null) {
for (Node curr: node.children) {
traversal(curr, result);
}
}
}
}
// Facorite
class Solution {
public List<Integer> preorder(Node root) {
List<Integer> result = new LinkedList<>();
Stack<Node> stack = new Stack<>();
if (root == null) return result; // edge case
stack.push(root);
while (!stack.isEmpty()) {
Node curr = stack.pop();
result.add(curr.val);
if (curr.children != null) {
for (int i = curr.children.size() - 1; i >= 0; i--) {
stack.push(curr.children.get(i));
}
}
}
return result;
}
}
class Solution {
public List<Integer> list = new ArrayList<>();
public List<Integer> preorder(Node root) {
if (root == null)
return list;
list.add(root.val);
for(Node node: root.children)
preorder(node);
return list;
}
}
//Iterative